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X^2-20X-3600=0
a = 1; b = -20; c = -3600;
Δ = b2-4ac
Δ = -202-4·1·(-3600)
Δ = 14800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14800}=\sqrt{400*37}=\sqrt{400}*\sqrt{37}=20\sqrt{37}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{37}}{2*1}=\frac{20-20\sqrt{37}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{37}}{2*1}=\frac{20+20\sqrt{37}}{2} $
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